* Calculation of weaver’s load
Assume total no. of looms= 50.
Sl no.
|
Occurance (x)
|
No. of x/loom/hr y
|
Time for each repair z (min)
|
Total time yz
|
1.
|
Warp break /hr/loom
|
3
|
.5
|
1.5
|
2.
|
Weft break /hr/loom
|
2
|
.4
|
0.8
|
3.
|
Trimming /hr/loom.
|
3
|
.3
|
0.9
|
4.
|
Skewering /hr/loom.
|
3
|
.3
|
0.9
|
5.
|
Shuttle trap/hr/loom
|
0.25
|
1
|
0.25
|
6.
|
Patrol /hr/loom.
|
4
|
.25
|
1.00
|
Total repair time/loom/hr=5.35
No. of looms/ weaver at standard work load= 50/5.35 = 9.34 =9
* Calculation
of weaver’s load: (Class)
Sl no.
|
Occurance (x)
|
No. of x /gr/loom
Y
|
Time for each repair
Z (min)
|
Total time yz (min)
|
1.
|
Warp break
|
1.2
|
0.80
|
0.96
|
2.
|
Weft break
|
0.3
|
0.5
|
0.15
|
3.
|
Slack ends.
|
0.1
|
0.5
|
0.05
|
4.
|
Pirn change.
|
3
|
0.2
|
0.06
|
Total repair time /loom /hr=1.76 mins
Maximum no. of loom which can be assigned to a weaver= 50/1.76 =28
(maximum work load 50 min/hr)
Minimum no. of loom which can be assigned to a weaver= 45/1.76 = 25
[ minimum work load 45 min/hr]
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